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A sum of money under compound interest doubles itself in 4 years. In how many years will it become 16 times itself? 

 

Option: 1

12 years


Option: 2

16 years


Option: 3

8 years


Option: 4

None of these


16 years 

 

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Posted by

Debjani Behera

A certain loan amounts, under compound interest, compounded annually earns an interest of Rs.1980 in the second year and Rs.2178 in the third year. How much interest did it earn in the first year?

Option: 1

Rs.1600


Option: 2

Rs.1800


Option: 3

 Rs.1900


Option: 4

None of these

 


xyz pqr abc year tt

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Posted by

wgqefiqyg

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Read the passage below and answer the following questions.

Cheating is considered a criminal offence under the Indian Penal Code. It is done to gain profit or advantage from another person by using some deceitful means. The person who deceives another knows for the fact that it would place the other person in an unfair situation. Cheating as an offence can be made punishable under Section 420 of the IPC. Scope of Section 415 Cheating is defined under Section 415 of the Indian Penal Code as whoever fraudulently or dishonestly deceives a person to induce that person to deliver a property to any person or to consent to retain any property. If a person intentionally induces a person to do or omit to do any act which he would not have done if he was not deceived to do so and the act has caused harm to that person in body, mind, reputation, or property, then the person who fraudulently, dishonestly or intentionally induced the other person is said to cheat. Any dishonest concealment of facts that can deceive a person to do an act that he would not have done otherwise is also cheating within the meaning of this section. Essential Ingredients of Cheating requires · deception of any person. Fraudulently or dishonestly inducing that person to deliver any property to any person or to consent that any person shall retain any property; or · intentionally inducing a person to do or omit to do anything which he would not do or omit if he were not so deceived, and the act or omission causes or is likely to cause damage or harm to that person in body, mind, reputation or property.

Deceit– a tort arising from an untrue or false statement of facts which are made by a person, recklessly or knowingly, with an intention that it shall be acted upon by the other person, who would suffer damages as a result. 

Fraud – a false or untrue representation of the fact, that is made with the knowledge of its falsity or without the belief in its truth or a reckless statement that may or may not be true, with an intention to induce a person or individual to act independent of it with the result that the person acts on it and suffers damages and harm. In other words, it is a wrong act or criminal deception with an intention to result in financial or personal gain.

Question :- D went to a moneylender, Z, for the loan. D intentionally pledges the gold article with Z taking the loan. D knows that the article is not made of gold. After a few days, D leaves the village. Decide.

Option: 1

-


Option: 2

D has committed cheating as well as fraud 
 


Option: 3

D has not committed the offence of cheating 

 


Option: 4

D has committed an act which is an offence of cheating as well as the tort of deceit


As per section 415 of IPC, D has intentionally pledged the gold article with Z, his intention is clearly to deceive Z and cause him financial loss hence D would be liable for the offence of Cheating. Actions of D are also held liable as a tort of deceit.

Hence option (d) is correct. 

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Posted by

Rishabh Jain

If f(x)=\cos x \cdot \cos 2 x \cdot \cos 4 x \cdot \cos 8 x \cdot \cos 16 x \text { then } f^{\prime}\left(\frac{\pi}{4}\right) \text { is }

Option: 1

\sqrt{2}


Option: 2

\frac{1}{\sqrt{2}}


Option: 3

1


Option: 4

None of these


\begin{aligned} & f(x)=\frac{2 \sin x \cdot \cos x \cdot \cos 2 x \cdot \cos 4 x \cdot \cos 8 x \cdot \cos 16 x}{2 \sin x}=\frac{\sin 32 x}{2^5 \sin x} \\ & \therefore \quad f^{\prime}(x)=\frac{1}{32} \cdot \frac{32 \cos 32 x \cdot \sin x-\cos x \cdot \sin 32 x}{\sin ^2 x} \\ & \quad f^{\prime}\left(\frac{\pi}{4}\right)=\frac{32 \cdot \frac{1}{\sqrt{2}}-\frac{1}{\sqrt{2}} \cdot 0}{32 \cdot\left(\frac{1}{\sqrt{2}}\right)^2}=\sqrt{2} \\ & \therefore \quad \end{aligned}

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Posted by

Nehul

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Consider f(x)=\left\{\begin{array}{cl}\frac{a+3 \cos x}{x^2}, & x<0 \\ b \tan \left\{\frac{\pi}{[x+3]}\right\}, & x \geq 0\end{array}\right. where [.] represents the greatest integer function. If f(x) is continuous at x=0, then 4 b^2+a is equal to

Option: 1

1


Option: 2

2


Option: 3

0


Option: 4

-1


For x=0 and x=0+h ;[x+3]=3
\mathrm{\begin{aligned} & \therefore \quad f(0)=b \tan \frac{\pi}{3}=b \sqrt{3} \\ & \text { R.H.L. }=\lim _{h \rightarrow 0} b \tan \frac{\pi}{[h+3]}=b \tan \frac{\pi}{3}=b \sqrt{3} \\ & \text { L.H.L. }=\lim _{h \rightarrow 0} \frac{a+3 \cos (0-h)}{(-h)^2}=\lim _{h \rightarrow 0} \frac{a+3 \cos h}{h^2} \\ & =\lim _{h \rightarrow 0} \frac{a+3\left(1-\frac{h^2}{2 !}+\frac{h^4}{4 !}-\ldots\right)}{h^2} \\ & =\lim _{h \rightarrow 0}\left[\frac{(a+3)}{h^2}-\frac{3}{2}+\text { powers of } h\right] \end{aligned} }
For left hand limit to exist, we must have a+3=0
\mathrm{\therefore a=-3 \, and \, \, in\, \, that\, \, case\, \, the\, \, L.H.L. =-\frac{3}{2} }
For continuity, we have
\mathrm{\begin{aligned} & b \sqrt{3}=-\frac{3}{2}=b \sqrt{3} \\ & \Rightarrow a=-3 \text { and } b=-\frac{1}{2} \sqrt{3} \Rightarrow 4 b^2+a=0 \end{aligned} }

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Posted by

seema garhwal

Let \small x=(9+4 \sqrt{5})^{19} , then x{x} ({⋅} denotes fractional part of x) is equal to 
 

Option: 1

2^{19}


Option: 2

3^{19}


Option: 3

1


Option: 4

None of these


\begin{aligned} & x=(9+4 \sqrt{5})^{19}=[x]+\{x\} \\ & \{x\}+(9-4 \sqrt{5})^{19}=1 \\ & x\{x\}+1=x \\ & x\{x\}=(9+4 \sqrt{5})^{19}-1 \end{aligned}

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Posted by

chirag

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If  C_r stands for { }^{\mathrm{n}} C_r \text {, } the sum of given series \frac{2(n / 2) !(n / 2) !}{n !}\left[C_0^2-2 C_1^2+3 C_2^2-\ldots \ldots+(-1)^n(n+1) C_n^2\right]

where n is an even positive integer, is

Option: 1

0


Option: 2

(-1)^{n / 2}(n+1)


Option: 3

(-1)^n(n+2)


Option: 4

(-1)^{n / 2}(n+2)


We have C_0^2-2 C_1^2+3 C_2^2-\ldots \ldots \ldots+(-1)^n(n+1) C_n^2=\left[C_0^2-C_1^2+C_2^2-\ldots \ldots .+(-1)^n C_n^2\right]-\left[C_1^2-2 C_2^2+3 C_3^2 \ldots \ldots+(-1)^n n \cdot C_n^2\right]

$$ \begin{aligned} & =\frac{2 \cdot \frac{n}{2} ! \frac{n}{2} !}{n !}\left[(-1)^{n / 2} \cdot\left(1+\frac{n}{2}\right) \frac{n !}{\frac{n}{2} ! \frac{n}{2} !}\right]=(-1)^{n / 2}(n+2) \\ & \end{aligned}Therefore the value of given expression

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Posted by

Ritika Harsh

The set of points where the function \mathrm{f(x)=|x-1| e^x}   is differentiable is

Option: 1

R


Option: 2

\mathrm{R-|1|}


Option: 3

\mathrm{R-|-1|}


Option: 4

\mathrm{R-|0|}


Since |x-1| is not differentiable at x=1. So.  \mathrm{f(x)=|x-1| c^{\prime}}  is not differentiable at x=1. Hence, the requried set is R-|1|.

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Posted by

Ritika Kankaria

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A steel rod of length 400 cm is clamped at the middle. The frequency of the fundamental mode for the longitudinal vibrations of the rod is  2.5K Hz . Find the speed of sound in steel.

 

Option: 1

20km/s


Option: 2

25km/s


Option: 3

15km/s


Option: 4

26km/s


\frac{\lambda }{2}=distance between two connected antinode

\frac{\lambda }{2}=4\\ \lambda=8M

frequency of fundamental mode is 

f=\frac{v}{\lambda }\\2.5\times10^{3}=\frac{v}{8}\\v=8\times2.5\times10^{3}\\v=20km/s

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Posted by

Anam Khan

If  \vec{A}=a y \hat{x}+b \times \hat{y}  then curl will be-

Option: 1

(a-b) \hat{z}


Option: 2

(b-a) \hat{z}


Option: 3

(a+b) \hat{z}


Option: 4

(a-b) \hat{x}


\vec{A}=a y \hat{x}+b x \hat{y}

{\nabla} \times \vec{A}= curl =\left|\begin{array}{ccc} \hat{\imath} & \hat{\jmath} & \hat{k} \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ a y & b x & 0 \end{array}\right|

\begin{aligned} & \vec{\nabla} \times \vec{A}=\hat{\imath}\left[\frac{\partial}{\partial y}(0)-\frac{\partial}{\partial z} b x\right]-\hat{j}\left[\frac{\partial}{\partial x} 0-\frac{\partial}{\partial z} a y\right] \\ &+\hat{k}\left[\frac{\partial}{\partial x} b x-\frac{\partial}{\partial y} a y\right] \end{aligned}

\\vec{\nabla} \times \vec{A}=i[0]-\hat{j}[0]+\hat{k}[b-a] \\
\vec{\nabla} \times \vec{A}=(b-a) \hat{z} \cdot

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Posted by

himanshu.meshram

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